호스팅 TIP > 기타 > SQL 문과 MongoDB 비교

시스템

	게시물 139건

SQL 문과 MongoDB 비교

글쓴이 : 최고관리자 날짜 : 2015-06-26 (금) 13:33 조회 : 8343

글주소 :

출처 : http://jy86.tistory.com/26

SQL 문장	Mongo 쿼리 문장
CREATE TALE USERS (a int, b int)	db.createCollection("mycoll")
INSERT INTO USERS VALUES (3,5)	db.users.insert({a:3, b:5})
SELECT a, b FROM USERS	db.users.find({}, {a:1, b:1})
SELECT * FROM users	db.users.find()
SELECT * FROM users WHERE age=33	db.users.find({age:33})
SELECT a,b FROM users WHERE age=33	db.users.find({age:33}, {a:1,b:1})
SELECT * FROM users WHERE age=33 ORDER BY name	db.users.find({age:33}).sort({name:1})
SELECT * FROM users WHERE age>33	db.users.find({'age':{$gt:33}})
SELECT * FROM users WHERE age<33	db.users.find({'age':{$lt:33}})
SELECT * FROM users WHERE name LIKE"%Joe%"	db.users.find({name:/Joe/})
SELECT * FROM users WHERE name LIKE "Joe%"	db.users.find({name:/^Joe/})
SELECT * FROM users WHERE age>33 AND age<=40	db.users.find({'age':{$gt:33,$lte:40}})
SELECT * FROM users ORDER BY name DESC	db.users.find().sort({name:-1})
SELECT * FROM users WHERE a=1 and b='q'	db.users.find({a:1,b:'q'})
SELECT * FROM users LIMIT 10 SKIP 20	SELECT * FROM users LIMIT 10 SKIP 20
SELECT * FROM users WHERE a=1 or b=2	db.users.find( { $or : [ { a : 1 } , { b : 2 } ] } )
SELECT * FROM users LIMIT 1	db.users.findOne()
SELECT DISTINCT last_name FROM users	db.users.distinct('last_name')
SELECT COUNT(*y) FROM users	db.users.count()

SELECT COUNT(*y) FROM users where AGE > 30	db.users.find({age: {'$gt': 30}}).count()
SELECT COUNT(AGE) from users	db.users.find({age: {'$exists': true}}).count()

CREATE INDEX myindexname ON users(name)	db.users.ensureIndex({name:1})
CREATE INDEX myindexname ON users(name,ts DESC)	db.users.ensureIndex({name:1,ts:-1})
EXPLAIN SELECT * FROM users WHERE z=3	db.users.find({z:3}).explain()
UPDATE users SET a=1 WHERE b='q'	db.users.update({b:'q'}, {$set:{a:1}}, false, true)
UPDATE users SET a=a+2 WHERE b='q'	db.users.update({b:'q'}, {$inc:{a:2}}, false, true)
DELETE FROM users WHERE z="abc"	db.users.remove({z:'abc'});

인기검색어